1910 United States House of Representatives elections
House elections for the 62nd U.S. Congress
The 1910 United States House of Representatives elections were held for the most part on November 8, 1910, while Maine and Vermont held theirs early in September, in the middle of President William Howard Taft's term. Elections were held for all 391 seats of the United States House of Representatives, representing 46 states, to the 62nd United States Congress
The conservative Taft contended with major factional splits within his Republican Party. Instead of using his position as president to bridge compromise, Taft alienated the progressive wing of the party, which had championed his predecessor, Theodore Roosevelt. While conservatives controlled the largest number of elected positions for Republicans, progressive politics had been what brought many voters to the polls. The clash of these units of the Republican Party, combined with the message of unity from the Democratic Party, was enough to allow the Democrats to take control of the House, ending 16 years in opposition. This was the first time the Socialist Party won a seat.
Issues
Protection was the ideological cement holding the Republican coalition together. High tariffs were used by Republicans to promise higher sales to business, higher wages to industrial workers, and higher demand for their crops to farmers. Progressive insurgents said it promoted monopoly. Democrats said it was a tax on the little man.
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