Superadditivity
property of a function

In mathematics, a function
f
{\displaystyle f}
is superadditive if
f
(
x
+
y
)
≥
f
(
x
)
+
f
(
y
)
{\displaystyle f(x+y)\geq f(x)+f(y)}
for all
x
{\displaystyle x}
and
y
{\displaystyle y}
in the domain of
f
.
{\displaystyle f.}
Similarly, a sequence
a
1
,
a
2
,
…
{\displaystyle a_{1},a_{2},\ldots }
is called superadditive if it satisfies the inequality
a
n
+
m
≥
a
n
+
a
m
{\displaystyle a_{n+m}\geq a_{n}+a_{m}}
for all
m
{\displaystyle m}
and
n
.
{\displaystyle n.}
The term "superadditive" is also applied to functions from a boolean algebra to the real numbers where
P
(
X
∨
Y
)
≥
P
(
X
)
+
P
(
Y
)
,
{\displaystyle P(X\lor Y)\geq P(X)+P(Y),}
such as lower probabilities.
Examples of superadditive functions
The map
f
(
x
)
=
x
2
{\displaystyle f(x)=x^{2}}
is a superadditive function for nonnegative real numbers because
f
(
x
+
y
)
=
(
x
+
y
)
2
=
x
2
+
y
2
+
2
x
y
=
f
(
x
)
+
f
(
y
)
+
2
x
y
≥
f
(
x
)
+
f
(
y
)
.
{\displaystyle f(x+y)=(x+y)^{2}=x^{2}+y^{2}+2xy=f(x)+f(y)+2xy\geq f(x)+f(y).}
The determinant is superadditive for nonnegative Hermitian matrix, that is, if
A
,
B
∈
Mat
n
(
C
)
{\displaystyle A,B\in {\text{Mat}}_{n}(\mathbb {C} )}
are nonnegative Hermitian then
det
(
A
+
B
)
≥
det
(
A
)
+
det
(
B
)
.
{\displaystyle \det(A+B)\geq \det(A)+\det(B).}
This follows from the Minkowski determinant theorem, which more generally states that
det
(
⋅
)
1
/
n
{\displaystyle \det(\cdot )^{1/n}}
is superadditive (equivalently, concave) for nonnegative Hermitian matrices of size
n
{\displaystyle n}
: If
A
,
B
∈
Mat
n
(
C
)
{\displaystyle A,B\in {\text{Mat}}_{n}(\mathbb {C} )}
are nonnegative Hermitian then
det
(
A
+
B
)
1
/
n
≥
det
(
A
)
1
/
n
+
det
(
B
)
1
/
n
.
{\displaystyle \det(A+B)^{1/n}\geq \det(A)^{1/n}+\det(B)^{1/n}.}
Horst Alzer proved that Hadamard's gamma function
H
(
x
)
{\displaystyle H(x)}
is superadditive for all real numbers
x
,
y
{\displaystyle x,y}
with
x
,
y
≥
1.5031.
{\displaystyle x,y\geq 1.5031.}
Mutual information
Properties
If
f
{\displaystyle f}
is a superadditive function whose domain contains
0
,
{\displaystyle 0,}
then
f
(
0
)
≤
0.
{\displaystyle f(0)\leq 0.}
To see this, simply set
x
=
0
{\displaystyle x=0}
and
y
=
0
{\displaystyle y=0}
in the defining inequality.
The negative of a superadditive function is subadditive.
Begin with the source’s own compact description: “Superadditivity” is property of a function. The dossier treats that line as a proposition to test through Superadditivity, property and function, not as a finished interpretation.
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