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Superadditivity

property of a function

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General referenceInterpretive dossier study · Crown Archives visual atlas
Record originEnglish Wikipedia
Text licenseCC BY-SA 4.0
Source revisionFeb 24, 2025
Entity authorityQ922087
Source-derived summary

In mathematics, a function

f

{\displaystyle f}

is superadditive if

f

(

x

+

y

)

f

(

x

)

+

f

(

y

)

{\displaystyle f(x+y)\geq f(x)+f(y)}

for all

x

{\displaystyle x}

and

y

{\displaystyle y}

in the domain of

f

.

{\displaystyle f.}

Similarly, a sequence

a

1

,

a

2

,

{\displaystyle a_{1},a_{2},\ldots }

is called superadditive if it satisfies the inequality

a

n

+

m

a

n

+

a

m

{\displaystyle a_{n+m}\geq a_{n}+a_{m}}

for all

m

{\displaystyle m}

and

n

.

{\displaystyle n.}

The term "superadditive" is also applied to functions from a boolean algebra to the real numbers where

P

(

X

Y

)

P

(

X

)

+

P

(

Y

)

,

{\displaystyle P(X\lor Y)\geq P(X)+P(Y),}

such as lower probabilities.

Examples of superadditive functions

The map

f

(

x

)

=

x

2

{\displaystyle f(x)=x^{2}}

is a superadditive function for nonnegative real numbers because

f

(

x

+

y

)

=

(

x

+

y

)

2

=

x

2

+

y

2

+

2

x

y

=

f

(

x

)

+

f

(

y

)

+

2

x

y

f

(

x

)

+

f

(

y

)

.

{\displaystyle f(x+y)=(x+y)^{2}=x^{2}+y^{2}+2xy=f(x)+f(y)+2xy\geq f(x)+f(y).}

The determinant is superadditive for nonnegative Hermitian matrix, that is, if

A

,

B

Mat

n

(

C

)

{\displaystyle A,B\in {\text{Mat}}_{n}(\mathbb {C} )}

are nonnegative Hermitian then

det

(

A

+

B

)

det

(

A

)

+

det

(

B

)

.

{\displaystyle \det(A+B)\geq \det(A)+\det(B).}

This follows from the Minkowski determinant theorem, which more generally states that

det

(

)

1

/

n

{\displaystyle \det(\cdot )^{1/n}}

is superadditive (equivalently, concave) for nonnegative Hermitian matrices of size

n

{\displaystyle n}

: If

A

,

B

Mat

n

(

C

)

{\displaystyle A,B\in {\text{Mat}}_{n}(\mathbb {C} )}

are nonnegative Hermitian then

det

(

A

+

B

)

1

/

n

det

(

A

)

1

/

n

+

det

(

B

)

1

/

n

.

{\displaystyle \det(A+B)^{1/n}\geq \det(A)^{1/n}+\det(B)^{1/n}.}

Horst Alzer proved that Hadamard's gamma function

H

(

x

)

{\displaystyle H(x)}

is superadditive for all real numbers

x

,

y

{\displaystyle x,y}

with

x

,

y

1.5031.

{\displaystyle x,y\geq 1.5031.}

Mutual information

Properties

If

f

{\displaystyle f}

is a superadditive function whose domain contains

0

,

{\displaystyle 0,}

then

f

(

0

)

0.

{\displaystyle f(0)\leq 0.}

To see this, simply set

x

=

0

{\displaystyle x=0}

and

y

=

0

{\displaystyle y=0}

in the defining inequality.

The negative of a superadditive function is subadditive.

Editorial summary

Begin with the source’s own compact description: “Superadditivity” is property of a function. The dossier treats that line as a proposition to test through Superadditivity, property and function, not as a finished interpretation.

Editorial reviewA dependable orientation record for establishing vocabulary, names and a first evidence trail. The current 429-word lead offers orientation but no explicit four-digit date, so chronology should not be assumed. The selected authority fields contribute no independent date. For this dossier, Superadditivity, property and function is the immediate research focus.
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This entry incorporates text from Superadditivity” on English Wikipedia. Contributors are listed in the page history. Text is available under the Creative Commons Attribution-ShareAlike 4.0 License. Selected authority identifiers and statements are retrieved from Wikidata under CC0; their references and qualifiers remain part of the verification path.