Singular integral
integral operator whose kernel is singular along the diagonal

In mathematics, singular integrals are central to harmonic analysis and are intimately connected with the study of partial differential equations. Broadly speaking a singular integral is an integral operator
T
(
f
)
(
x
)
=
∫
K
(
x
,
y
)
f
(
y
)
d
y
,
{\displaystyle T(f)(x)=\int K(x,y)f(y)\,dy,}
whose kernel function
K
:
R
n
×
R
n
→
R
{\displaystyle K:\mathbb {R} ^{n}\times \mathbb {R} ^{n}\to \mathbb {R} }
is singular along the diagonal
x
=
y
{\displaystyle x=y}
. Specifically, the singularity is such that
|
K
(
x
,
y
)
|
{\displaystyle |K(x,y)|}
is of size
|
x
−
y
|
−
n
{\displaystyle |x-y|^{-n}}
asymptotically as
|
x
−
y
|
→
0
{\displaystyle |x-y|\to 0}
. Since such integrals may not in general be absolutely integrable, a rigorous definition must define them as the limit of the integral over
|
y
−
x
|
→
ϵ
{\displaystyle |y-x|\to \epsilon }
as
ϵ
→
0
{\displaystyle \epsilon \to 0}
, but in practice this is a technicality. Usually further assumptions are required to obtain results such as their boundedness on Lp spaces, for example
L
p
(
R
n
)
{\displaystyle L^{p}(\mathbb {R} ^{n})}
.
The Hilbert transform
The archetypal singular integral operator is the Hilbert transform
H
{\displaystyle H}
. It is given by convolution against the kernel
K
(
x
)
=
1
/
(
π
x
)
{\displaystyle K(x)=1/(\pi x)}
for
x
{\displaystyle x}
in
R
{\displaystyle \mathbb {R} }
. More precisely,
H
(
f
)
(
x
)
=
1
π
lim
ε
→
0
∫
|
x
−
y
|
>
ε
1
x
−
y
f
(
y
)
d
y
.
{\displaystyle H(f)(x)={\frac {1}{\pi }}\lim _{\varepsilon \to 0}\int _{|x-y|>\varepsilon }{\frac {1}{x-y}}f(y)\,dy.}
The most straightforward higher dimension analogues of these are the Riesz transforms, which replace
K
(
x
)
=
1
/
x
{\displaystyle K(x)=1/x}
with
K
i
(
x
)
=
x
i
|
x
|
n
+
1
{\displaystyle K_{i}(x)={\frac {x_{i}}{|x|^{n+1}}}}
where
i
=
1
,
.
.
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