Step potential
system in quantum mechanics

In quantum mechanics and scattering theory, the one-dimensional step potential is an idealized system used to model incident, reflected and transmitted matter waves. The problem consists of solving the time-independent Schrödinger equation for a particle with a step-like potential in one dimension. Typically, the potential is modeled as a Heaviside step function.
Calculation
Schrödinger equation and potential function
The time-independent Schrödinger equation for the wave function
ψ
(
x
)
{\displaystyle \psi (x)}
is
H
^
ψ
(
x
)
=
[
−
ℏ
2
2
m
d
2
d
x
2
+
V
(
x
)
]
ψ
(
x
)
=
E
ψ
(
x
)
,
{\displaystyle {\hat {H}}\psi (x)=\left[-{\frac {\hbar ^{2}}{2m}}{\frac {d^{2}}{dx^{2}}}+V(x)\right]\psi (x)=E\psi (x),}
where Ĥ is the Hamiltonian, ħ is the reduced Planck constant, m is the mass, E the energy of the particle. The step potential is simply the product of V0, the height of the barrier, and the Heaviside step function:
V
(
x
)
=
{
0
,
x
<
0
V
0
,
x
≥
0
{\displaystyle V(x)={\begin{cases}0,&x<0\\V_{0},&x\geq 0\end{cases}}}
The barrier is positioned at x = 0, though any position x0 may be chosen without changing the results, simply by shifting position of the step by −x0.
The first term in the Hamiltonian,
−
ℏ
2
2
m
d
2
d
x
2
ψ
{\textstyle -{\frac {\hbar ^{2}}{2m}}{\frac {d^{2}}{dx^{2}}}\psi }
is the kinetic energy of the particle.
Solution
The step divides space in two parts: x < 0 and x > 0. In any of these parts the potential is constant, meaning the particle is quasi-free, and the solution of the Schrödinger equation can be written as a superposition of left and right moving waves (see free particle)
ψ
1
(
x
)
=
(
A
→
e
i
k
1
x
+
A
←
e
−
i
k
1
x
)
x
<
0
,
{\displaystyle \psi _{1}(x)=\left(A_{\rightarrow }e^{ik_{1}x}+A_{\leftarrow }e^{-ik_{1}x}\right)\quad x<0,}
ψ
2
(
x
)
=
(
B
→
e
i
k
2
x
+
B
←
e
−
i
k
2
x
)
x
>
0
{\displaystyle \psi _{2}(x)=\left(B_{\rightarrow }e^{ik_{2}x}+B_{\leftarrow }e^{-ik_{2}x}\right)\quad x>0}
where subscripts 1 and 2 denote the regions x < 0 and x > 0 respectively, the subscripts (→) and (←) on the amplitudes A and B denote the direction of the particle's velocity vector: right and left respectively.
The wave vectors in the respective regions being
k
1
=
2
m
E
/
ℏ
2
,
{\displaystyle k_{1}={\sqrt {2mE/\hbar ^{2}}},}
k
2
=
2
m
(
E
−
V
0
)
/
ℏ
2
{\displaystyle k_{2}={\sqrt {2m(E-V_{0})/\hbar ^{2}}}}
both of which have the same form as the De Broglie relation (in one dimension)
p
=
ℏ
k
{\displaystyle p=\hbar k}
.
Boundary conditions
The coefficients A, B have to be found from the boundary conditions of the wave function at x = 0.
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