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Faulhaber's formula

expression for sums of powers

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Record originEnglish Wikipedia
Text licenseCC BY-SA 4.0
Source revisionSep 16, 2026
Entity authorityQ1398443 ↗
Source-derived summary

In mathematics, Faulhaber's formula, named after the early 17th century mathematician Johann Faulhaber, expresses the sum of the

p

{\displaystyle p}

th powers of the first

n

{\displaystyle n}

positive integers

∑

k

=

1

n

k

p

=

1

p

+

2

p

+

3

p

+

⋯

+

n

p

{\displaystyle \sum _{k=1}^{n}k^{p}=1^{p}+2^{p}+3^{p}+\cdots +n^{p}}

as a polynomial in

n

{\displaystyle n}

. In modern notation, Faulhaber's formula is

∑

k

=

1

n

k

p

=

1

p

+

1

∑

r

=

0

p

(

p

+

1

r

)

B

r

+

n

p

+

1

−

r

.

{\displaystyle \sum _{k=1}^{n}k^{p}={\frac {1}{p+1}}\sum _{r=0}^{p}{\binom {p+1}{r}}B_{r}^{+}n^{p+1-r}.}

Here,

(

p

+

1

r

)

{\textstyle {\binom {p+1}{r}}}

is the binomial coefficient "

p

+

1

{\displaystyle p+1}

choose

r

{\displaystyle r}

", and the

B

r

+

{\displaystyle B_{r}^{+}}

are the second Bernoulli numbers, identical to the first ones except for

B

1

+

=

1

2

{\textstyle B_{1}^{+}={\frac {1}{2}}}

.

The result: Faulhaber's formula

Faulhaber's formula concerns expressing the sum of the

p

{\displaystyle p}

th powers of the first

n

{\displaystyle n}

positive integers

∑

k

=

1

n

k

p

=

1

p

+

2

p

+

3

p

+

⋯

+

n

p

{\displaystyle \sum _{k=1}^{n}k^{p}=1^{p}+2^{p}+3^{p}+\cdots +n^{p}}

as a

(

p

+

1

)

{\displaystyle (p+1)}

th-degree polynomial function of

n

{\displaystyle n}

.

The first few examples are well known. For

p

=

0

{\displaystyle p=0}

, we have

∑

k

=

1

n

k

0

=

∑

k

=

1

n

1

=

n

.

{\displaystyle \sum _{k=1}^{n}k^{0}=\sum _{k=1}^{n}1=n.}

For

p

=

1

{\displaystyle p=1}

, we have the triangular numbers

∑

k

=

1

n

k

1

=

∑

k

=

1

n

k

=

n

(

n

+

1

)

2

=

1

2

(

n

2

+

n

)

.

{\displaystyle \sum _{k=1}^{n}k^{1}=\sum _{k=1}^{n}k={\frac {n(n+1)}{2}}={\frac {1}{2}}(n^{2}+n).}

For

p

=

2

{\displaystyle p=2}

, we have the square pyramidal numbers

∑

k

=

1

n

k

2

=

n

(

n

+

1

)

(

2

n

+

1

)

6

=

1

3

(

n

3

+

3

2

n

2

+

1

2

n

)

.

{\displaystyle \sum _{k=1}^{n}k^{2}={\frac {n(n+1)(2n+1)}{6}}={\frac {1}{3}}(n^{3}+{\tfrac {3}{2}}n^{2}+{\tfrac {1}{2}}n).}

The coefficients of Faulhaber's formula in its general form involve the second Bernoulli numbers

B

j

+

{\displaystyle B_{j}^{+}}

which nearly coincide with the first Bernoulli numbers denoted

B

j

−

{\displaystyle B_{j}^{-}}

(or simply

B

j

{\displaystyle B_{j}}

); the sole exception is at

j

=

1

{\displaystyle j=1}

, where

B

1

−

=

−

1

2

{\displaystyle B_{1}^{-}=-{\tfrac {1}{2}}}

but

B

1

+

=

1

2

{\displaystyle B_{1}^{+}={\tfrac {1}{2}}}

. The Bernoulli numbers begin

B

0

=

1

B

1

+

=

1

2

B

2

=

1

6

B

3

=

0

B

4

=

−

1

30

B

5

=

0

B

6

=

1

42

B

7

=

0

,

{\displaystyle {\begin{aligned}B_{0}&=1&B_{1}^{+}&={\tfrac {1}{2}}&B_{2}&={\tfrac {1}{6}}&B_{3}&=0\\B_{4}&=-{\tfrac {1}{30}}&B_{5}&=0&B_{6}&={\tfrac {1}{42}}&B_{7}&=0,\end{aligned}}}

Then Faulhaber's formula is that

∑

k

=

1

n

k

p

=

1

p

+

1

∑

r

=

0

p

(

p

+

1

r

)

B

r

+

n

p

+

1

−

r

.

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This entry incorporates text from “Faulhaber's formula” on English Wikipedia. Contributors are listed in the page history. Text is available under the Creative Commons Attribution-ShareAlike 4.0 License. Selected authority identifiers and statements are retrieved from Wikidata under CC0; their references and qualifiers remain part of the verification path.