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Lebesgue's density theorem

theorem that, the density of a Lebesgue measurable set in Euclidean space is exists and is 0 or 1 almost everywhere

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Record originEnglish Wikipedia
Text licenseCC BY-SA 4.0
Source revisionJun 29, 2026
Entity authorityQ842953
Source-derived summary

In mathematics, Lebesgue's density theorem states that for any Lebesgue measurable set

A

R

n

{\displaystyle A\subseteq \mathbb {R} ^{n}}

, the "density" of

A

{\displaystyle A}

is 0 or 1 at almost every point in

R

n

{\displaystyle \mathbb {R} ^{n}}

. Additionally, the "density" of

A

{\displaystyle A}

is 1 at almost every point of

A

{\displaystyle A}

. Intuitively, this means that the boundary of

A

{\displaystyle A}

, the set of points in

A

{\displaystyle A}

for which all neighborhoods are partially in

A

{\displaystyle A}

and partially outside

A

{\displaystyle A}

, is of measure zero.

Statement

Let

μ

{\displaystyle \mu }

be the Lebesgue measure on the Euclidean space and

A

R

n

{\displaystyle A\subseteq \mathbb {R} ^{n}}

be a Lebesgue measurable set. Let

x

R

n

{\displaystyle x\in \mathbb {R} ^{n}}

and let

B

{\displaystyle B}

ε

(

x

)

{\displaystyle (x)}

denote the open ball of radius

ε

{\displaystyle \varepsilon }

centered at

x

{\displaystyle x}

. Define the density at a point

x

{\displaystyle x}

d

A

(

x

)

=

lim

ε

0

μ

(

A

B

ε

(

x

)

)

μ

(

B

ε

(

x

)

)

{\displaystyle \qquad \qquad d_{A}(x)=\lim _{\varepsilon \to 0}{\frac {\mu (A\cap B_{\varepsilon }(x))}{\mu (B_{\varepsilon }(x))}}}

For example, given a square in the plane, the density at every point inside the square is 1, on the edges is 1/2, and at the corners is 1/4. The set of points in the plane at which the density is neither 0 nor 1 is non-empty (the square boundary), but it is of measure zero.

The Lebesgue density theorem is a particular case of the Lebesgue differentiation theorem.

Thus, this theorem is also true for every finite Borel measure on

A

R

n

{\displaystyle A\subseteq \mathbb {R} ^{n}}

instead of Lebesgue measure, as proven in sections 2.8–2.9 of Federer's Geometric Measure Theory, 1969.

See also

Lebesgue differentiation theorem – Mathematical theorem in real analysis

References

This article incorporates material from Lebesgue density theorem on PlanetMath, which is licensed under the Creative Commons Attribution/Share-Alike License.

Editorial summary

Begin with the source’s own compact description: “Lebesgue's density theorem” is theorem that, the density of a Lebesgue measurable set in Euclidean space is exists and is 0 or 1 almost everywhere. The dossier treats that line as a proposition to test through Lebesgue's, density and theorem, not as a finished interpretation.

Editorial reviewA concise reference frame for defining the subject, testing terminology and identifying the institution closest to the evidence. The current lead gives the account dated anchors—1969—that can be checked directly. The selected authority fields contribute no independent date. For this dossier, Lebesgue's, density and theorem is the immediate research focus.
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This entry incorporates text from Lebesgue's density theorem” on English Wikipedia. Contributors are listed in the page history. Text is available under the Creative Commons Attribution-ShareAlike 4.0 License. Selected authority identifiers and statements are retrieved from Wikidata under CC0; their references and qualifiers remain part of the verification path.